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Which number is divisible by both 2 and 3?
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126
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100
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123
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133
That's Correct!
It's Wrong!
The number 126 is divisible by both 2 and 3 because it is an even number (divisible by 2) and the sum of its digits (1+2+6) is 9, which is divisible by 3. Therefore, 126 satisfies the conditions of being divisible by both 2 and 3.
