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A grocer sells 100 kg of jaggery partly at 10% profit and partly at 20% profit, gaining 12% on his outlay. How much does he sell at 10% profit ?
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80 Kg
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88 Kg
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75 Kg
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None of the above
That's Correct!
It's Wrong!
The grocer sells 80 kg of jaggery at a 10% profit. This can be determined by setting up a system of equations. Let x represent the amount of jaggery sold at a 10% profit and y represent the amount sold at a 20% profit. We know that x + y = 100 (since the total amount sold is 100 kg) and that 0.10x + 0.20y = 0.12(100) (since the overall profit is 12% of the total outlay). By solving this system of equations, we find that x = 80 and y = 20. Therefore, the grocer sells 80 kg at a 10% profit.
